求极限limx→α+[(lnx-lnα)/(x-α)]．
limx→α+[(lnx-lnα)/(x-α)]=limx→α+ln(x/α)1/(x-α)=limx→α+ln{[1+(x-α)/x]α/x-α}1/α=ln e1/α=1/α．
求极限limx→α+[(lnx-lnα)/(x-α)]．
limx→α+[(lnx-lnα)/(x-α)]=limx→α+ln(x/α)1/(x-α)=limx→α+ln{[1+(x-α)/x]α/x-α}1/α=ln e1/α=1/α．
