∫∫Dx√ydσ,其中D是由y=x2和x=y2所围区域．
∫∫Dx√ydσ= ∫01dy∫y2√yx√ydx = ∫01√y[(1/2)x2∣y2√y)dy=(1/2)∫01(y√y-y4•√y)dy=(1/2)[(2/5)y5/2-(2/11)y11/2)∣01) =6/55
∫∫Dx√ydσ,其中D是由y=x2和x=y2所围区域．
∫∫Dx√ydσ= ∫01dy∫y2√yx√ydx = ∫01√y[(1/2)x2∣y2√y)dy=(1/2)∫01(y√y-y4•√y)dy=(1/2)[(2/5)y5/2-(2/11)y11/2)∣01) =6/55
