已知方程exy+y-cosx2=3确定函数y=y(x),求dy/dx.
令F(x,y)=exy+y-cosx2-3,则Fx′,=yxy+2xsinx2,Fy′=xexy+1 所以dy/dx=-(Fx′/Fy′)=-[(yexy+2xsinx2)/xexy+1]
已知方程exy+y-cosx2=3确定函数y=y(x),求dy/dx.
令F(x,y)=exy+y-cosx2-3,则Fx′,=yxy+2xsinx2,Fy′=xexy+1 所以dy/dx=-(Fx′/Fy′)=-[(yexy+2xsinx2)/xexy+1]