若向量组
a1=
(1
0
2),
a2=
(-1
2
2),
a3=
(3
k
8)
线性相关，则k=____
1 分析：|a1,a2,a3|= |1 -1 3| |0 2 k| |2 2 8| =16-2k-12-2k =-4k+4=0,所以k=1
若向量组
a1=
(1
0
2),
a2=
(-1
2
2),
a3=
(3
k
8)
线性相关，则k=____
1 分析：|a1,a2,a3|= |1 -1 3| |0 2 k| |2 2 8| =16-2k-12-2k =-4k+4=0,所以k=1
