设X~N(1.5,4),求:
(1)P(X<3.5);
(2)P(X<-4);
(3)P(X>2);
(4)P(|X|<3).
μ=1.5,σ2=4,σ=2. (1)P(x<3.5)=φ[(3.5-1.5)/2]=φ(1)=0.8413. (2)P(x<-4)=φ[(-4-1.5)/2]=φ(-2.75) =1-φ(2.75)=0.0030. (3)P(X>2)=1-P(X≤2)=1-φ[(2-1.5)/2] =1-φ(0.25)=1-0.5987=0.4013. (4)P(|X|<3)=P(-3<X<3) =φ[(3-1.5)/2]-φ[(-3-1.5)/2] =φ(0.75)-φ(-2.25) =φ(0.75)-1+φ(2.25) =0.7612.