为自己加油

设z=f(u，υ，y)=e^usinv+y³，其中u=2x+u，υ=xy，求∂z/∂x，∂z/∂y．

∂z/∂x=∂f/∂u•∂u/∂x+∂f/∂υ•∂υ/∂x =e^usinυ•2+e^ucosυ•y =e^2x+y[2sin(xy)+ycos(xy)]， ∂z/∂y=∂f/∂u•∂u/∂y+∂f/∂υ•∂υ/∂y+∂f/∂y =e^usinv•1+e^ucos•x+3y² =e^2x+y[sin(xy)+xcos(xy)]+3y²．