某小班8名幼儿的身高分别为0.83m,0.96m,1.15m,0.90m,1.06m,0.9m,1.12m,1.08m,求他们各自的离差。
(1)首先求平均值:X(上面有横线)=(X1+X2+X3+…Xn)/N=(0.83+0.96+1.15+0.90+1.06+0.9+1.12+1.08)/8=1(2)根据公式D=X-X(上面有横线),代入数据:D1=X1-X(上面有横线)=0.83-1=-0.17。D2=X2-X(上面有横线)=0.96-1=-0.04。D3=X3-X(上面有横线)=1.15-1=0.15。D4=X4-X(上面有横线)=0.90-1=-0.10。D5=X5-X(上面有横线)=1.60-1=0.06。D6=X6-X(上面有横线)=0.90-1=-0.10。D7=X7-X(上面有横线)=1.12-1=0.12。D8=X8-X(上面有横线)=1.08-1=0.08。