矿井某测风站系三心拱砌碹巷道,巷道宽2.4m,墙高1.2m,经机械风表测量后,查得的校正风速为4.5 m/S,试计算通过该处的风量。(.K的系数为0.4)
解:根据公式得: 1S=0.262×2.42+2.4×1.2=4.39㎡
2V实=V效×K= 4.5×(.4.39-0.4)÷4.39=4.09(.m/s)
3Q= V实×S=4.09×4.39=17.96(.m3/s)
矿井某测风站系三心拱砌碹巷道,巷道宽2.4m,墙高1.2m,经机械风表测量后,查得的校正风速为4.5 m/S,试计算通过该处的风量。(.K的系数为0.4)
解:根据公式得: 1S=0.262×2.42+2.4×1.2=4.39㎡
2V实=V效×K= 4.5×(.4.39-0.4)÷4.39=4.09(.m/s)
3Q= V实×S=4.09×4.39=17.96(.m3/s)
