设∑是上半球面x2+y2+z2=R2(z≥0，R﹥0)，则关于面积的曲面积分∫∫∑[sin(x2+y2+z2)+(x2+y2-2z2)]ds为()
A.2πR2sinR2 B.4πR2sinR2 C.πR2sinR2 D.3πR2sinR2正确答案A
设∑是上半球面x2+y2+z2=R2(z≥0，R﹥0)，则关于面积的曲面积分∫∫∑[sin(x2+y2+z2)+(x2+y2-2z2)]ds为()
A.2πR2sinR2 B.4πR2sinR2 C.πR2sinR2 D.3πR2sinR2正确答案A
