设函数f(u)连续，区或D={(x，y)|x2+y2≤2y}，则∫∫Df(xy)dxdy等于()
A.∫-11dx∫-√1-x2√1-x2f(xy)dy B.∫0πdθ∫02sinθf(r2sinθcosθ)dr C.2∫02dy∫0√2y-y2f(xy)dx D.∫0πdθ∫02sinθf(r2sinθcosθ)rdr正确答案D
设函数f(u)连续，区或D={(x，y)|x2+y2≤2y}，则∫∫Df(xy)dxdy等于()
A.∫-11dx∫-√1-x2√1-x2f(xy)dy B.∫0πdθ∫02sinθf(r2sinθcosθ)dr C.2∫02dy∫0√2y-y2f(xy)dx D.∫0πdθ∫02sinθf(r2sinθcosθ)rdr正确答案D
