求下列由方程所确定的隐函数的导数或偏导数:
(1)设xy-iny=a,求dy/dx;
(2)设In√(x2+y2)=arctan(y/x),求dy/dx;
(3)设x+y+z=e-(x+y+z),求∂z/∂x和∂z/∂y;
(4)设zx=yz,求∂z/∂x和∂z/∂y;
(5)设x+2y+2z-2√xyz=0,求∂z/∂x和∂z/∂y;
(6)设x2-4x+y2+z2=0,求∂x/∂y和∂x/∂z.
(1)设F(X,y)=xy-lny-a•则∂F/∂x=y,∂F/∂y=x-1/y ∴dy/dx=Fx/Fy=y/(1/y-x)=y2/(1-xy) (2)设F(x,y)=In√(x2+y2)-arctan(y/x),则 Fx=(1/√x2+y2)•1/[2√(x2+y2)]•2x-[-(y/x2)]/ (1+y2/x2)=x/(x2+y2)+y/(x2+y2)=(x+y)/ (x2+y2) ∴dy/dx=-(Fx/Fy)=(x+y)/(x-y) (3)设F(x,y,z)=x+y+z-e-(x+y+z),则 Fx=1-e-(x+y+z)•(-1)=1+e-(x+y+z) Fy=1-e-(x+y+z)•(-1)=1+e-(x+y+z) Fz=1-e-(x+y+z)•(-1)=1+e-(x+y+z) ∴∂z/∂x=-(Fx/Fz)=-1,∂z/∂y=-(Fx/Fz)=-1 (4)设F(x,y,z)=zx-yz,则: Fx=zxlnz,Fy=-zyz-1,Fz=xzx-1-yzlny ∴∂z/∂x=-(Fx/Fz)=zxlnz/(yz-xzx-1)=zx+1lnz/(-zx+2yzlny) =zlnz/(zlny-x)(∵zx=yz) ∂z/∂y=-(Fy/Fz)=yz-1z/(xzx-1-yzlny)= yz-1z2/(xzx-zyzlny)=z2/[y(x-zlny)](∵zx=yz) (5)设F(x,y,z)=x+2y+2x-2√xyz,则: Fx=1-2•(1/2)•(yz/√xyz)=1-yz/√xyz Fy=2-2•(1/2)•(xz/√xyz)=2-xz/√xyz Fz=2-2•(1/2)•(xy/√xyz)=2-xy/√xyz ∴∂z/∂x=-(Fx/Fz)=(yz-√xyz)/(2√xyz-xy) ∂z/∂y=-(Fy/Fz)=(xz-2√xyz)/(2√xyz-xy) (6)设F(x,y,z)=x2-4x+y2+z2,则: Fx=2x-4,Fy=2y,Fz=2z ∴∂x/∂y=-(Fy/Fx)=-[2y(2x-4)]=y/(2-x) ∂x/∂z=-(Fz/Fx)=-[2z/(2x-4)]=z/(2-x)