设ƒ(x)是定义在实数域上的一个函数，且ƒ(x-1)=x2+x+1，则ƒ[1/(x-1)]=()
A.1/x2+1/x+1 B.1/(x-1)2+1/(x-1)+1 C.．1/(x2+x+1) D.1/(x-1)2+3/(x-1)+3正确答案D
设ƒ(x)是定义在实数域上的一个函数，且ƒ(x-1)=x2+x+1，则ƒ[1/(x-1)]=()
A.1/x2+1/x+1 B.1/(x-1)2+1/(x-1)+1 C.．1/(x2+x+1) D.1/(x-1)2+3/(x-1)+3正确答案D
