为自己加油

求(1-sin⁶α-cos⁶α)/(1-sin⁴α-cos⁴α)的值．

(1-sin⁶α-cos⁶α/1-sin⁴α-cos⁴α)=[1-(sin²α+cos²α)(sin²α-sin²αcos²α+cos²α)]/[1-(1-2sin²αcos²α)]=[1-(1-3sin²αcos²α)]/[1-(1-2sin²αcos²α)]=3/2