计算：(1)2(lg√2)2+lg√2·lg5+√(lg√2)2-lg2+1；
(2)(1092125+log425+log5)(log52+log254+log1258)．
(1)原式=lg√2(2lg√2+lg5)+√(lg√2-1)2 =lg√2(lg2+lg5)+∣lg√2-1∣ =lg√2+1-lg√2 (2)原式=[log253+(log225/log24)+(log25/log28)] [log52+(log54/log525)+(log58/log5125)] =[3log25+(2log25/2log22)+(log25/3log22)] [log52+(2log52/2log55)+(3log52/3log55)] =(3+1+1/3)log25·3log52 =13·(log55/log52)·log5 2=13．
