∫[(1+cos2x)/(1+cos2x)]dx
∫[(1+cos2x)/(1+cos2x)]dx=∫[(1+cos2x)/[cos2x+sin2x+cos2x-sin2x)]dx =1/2∫[(1+cos2x)/cos2x]dx=1/2∫sec2xdx+1/2∫dx =1/2tanx+(1/2)x+C.
∫[(1+cos2x)/(1+cos2x)]dx
∫[(1+cos2x)/(1+cos2x)]dx=∫[(1+cos2x)/[cos2x+sin2x+cos2x-sin2x)]dx =1/2∫[(1+cos2x)/cos2x]dx=1/2∫sec2xdx+1/2∫dx =1/2tanx+(1/2)x+C.