设y=2x3arccosx+(x2-2)√1-x2,求dy.
(6x2arccosx-x(3x2-2)+2x√1-x2)dx 分析 y′=6x2arccosx-2x2/√1-x2+2x√1-x2-x(x2-2)/√1-2 =6x2arccos-[x(3x2-2)/√1-x2]+2x√1-x 2 所以dy=(6x2arccosx-x(3x2-2)+2x√1-x2)dx
设y=2x3arccosx+(x2-2)√1-x2,求dy.
(6x2arccosx-x(3x2-2)+2x√1-x2)dx 分析 y′=6x2arccosx-2x2/√1-x2+2x√1-x2-x(x2-2)/√1-2 =6x2arccos-[x(3x2-2)/√1-x2]+2x√1-x 2 所以dy=(6x2arccosx-x(3x2-2)+2x√1-x2)dx