解下列方程：
(1)
|ααx|
|mmm|
|bxb|
=0(m≠0)；
(2)
|15-2x1110|
|11-3x1716|
|7-x1413|
=0．
(1) |α α x| |m m m| |b x b| =m |1 α x| |1 1 1| |b x b| =m |0 0 x-α| |1 1 1 | |0 x-b 0 | =m(x-b)(x-α)=0 又m≠0，所以 x=α或x=b (2) |15-2x 11 10| |11-3x 17 16| | 7-x 14 13| = |15-2x 1 10| |11-3x 1 16| | 7-x 1 13| =9(x+4)-72=0 所以 x=4
