若|α|<1,|b|<1,求极限limn→∞[(1+α+α2+…+αn)/(1+b+b2+…bn)].
limn→∞(1+α+α2+…+αn)/(1+b+b2+…bn) =limn→∞[(1+α+…αn)(1-α)(1-b)]/(1+b+…bn)(1-b)(1-α) =limn→∞=(1-αn+1)(1-b)/(1-bn+1)(1-α)=(1-b)/(1-α)limn→∞(1-αn+1)/(1-bn+1)=(1-b)/(1-α).
若|α|<1,|b|<1,求极限limn→∞[(1+α+α2+…+αn)/(1+b+b2+…bn)].
limn→∞(1+α+α2+…+αn)/(1+b+b2+…bn) =limn→∞[(1+α+…αn)(1-α)(1-b)]/(1+b+…bn)(1-b)(1-α) =limn→∞=(1-αn+1)(1-b)/(1-bn+1)(1-α)=(1-b)/(1-α)limn→∞(1-αn+1)/(1-bn+1)=(1-b)/(1-α).