求下列矩阵的秩：
(2-1211
11-102
25-4-29
33-1-18)
A= (2 -1 2 1 1 1 1 -1 0 2 2 5 -4 -2 9 3 3 -1 -1 8) → (1 1 -1 0 2 0 -3 4 1 -3 0 3 -2 -2 5 0 0 2 -1 2) → (1 1 -1 0 2 0 3 -2 -2 5 0 0 2 -1 2 0 0 2 -1 2) → (1 1 -1 0 2 0 3 -2 -2 5 0 0 2 -1 2 0 0 0 0 0) r(A)=3．
求下列矩阵的秩：
(2-1211
11-102
25-4-29
33-1-18)
A= (2 -1 2 1 1 1 1 -1 0 2 2 5 -4 -2 9 3 3 -1 -1 8) → (1 1 -1 0 2 0 -3 4 1 -3 0 3 -2 -2 5 0 0 2 -1 2) → (1 1 -1 0 2 0 3 -2 -2 5 0 0 2 -1 2 0 0 2 -1 2) → (1 1 -1 0 2 0 3 -2 -2 5 0 0 2 -1 2 0 0 0 0 0) r(A)=3．
