设曲线积分的路径为y=x2，则∫(0,0)(1,1)xydx+(y-x)dy=____．
1/12。解析：∫(0,0)(1,1)xydx+(y-x)dy=∫01[x•x2+(x2-x)•2x]dx=∫01(3x3-2x2)dx=(3/4)x4∣01-(2/3)x3∣01=1/12
设曲线积分的路径为y=x2，则∫(0,0)(1,1)xydx+(y-x)dy=____．
1/12。解析：∫(0,0)(1,1)xydx+(y-x)dy=∫01[x•x2+(x2-x)•2x]dx=∫01(3x3-2x2)dx=(3/4)x4∣01-(2/3)x3∣01=1/12
