用三重积分计算下列曲面所围成的立体的体积:
(1)z=6-x2-y2及z=√x2+y2;
(2)z=√5-x2-y2及x2+y2=4z.
(1)由题意设x=rcosθ,y=rsinθ,z=z,则: V=∫∫∫Ωdυ=∫02πdθ∫02dr ∫r6-r2rdz=∫02πdθ∫02 (6r-r3-r2)dr=∫02π(3r2-r4/4-r3/3) ∣02dθ=∫02π(16/3)dθ=(32/3)π (2)由题意设x=rcosθ,y=rsinθ,z=z,则: V=∫∫∫Ωdυ=∫02πdθ∫02dr ∫r2/4√5-r2rdz=∫02πdθ∫02 (r√5-r2-r3/4)dr =∫02π[-(1/4)]•(1/√5-r2)∣02dθ=-(1/4) ∫02π(1-√5/5)dθ=(2/3)π(5√5-4)