设z=z+y+f(x-y),若当y=0时z=sinx,求函数z.
当y=0时,z=x+0+f(x-0)=x+f(x) 由题设知 x+f(x)=sinx 于是 f(x)=sinx-x 从而有 f(x-y)=sin(x-y)-(x-y) 因此 z=x+y+f(x-y)=sin(x-y)+2y.
设z=z+y+f(x-y),若当y=0时z=sinx,求函数z.
当y=0时,z=x+0+f(x-0)=x+f(x) 由题设知 x+f(x)=sinx 于是 f(x)=sinx-x 从而有 f(x-y)=sin(x-y)-(x-y) 因此 z=x+y+f(x-y)=sin(x-y)+2y.